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x2 - 2x - 3 How would you remove the discontinuity of f (x) = at 3? In x2 - 5x + 6 other words,

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x2 - 2x - 3 How would you "remove the discontinuity" of f (x) = at 3? In x2 - 5x + 6 other words, how would you define f(3) so as to make f continuous at 3? This question wasn't answered

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