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Xn+1=(aXn)modm Then it can be shown that if m is prime and if a given value of a produces the maximum period of m1, then

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Xn+1=(aXn)modm Then it can be shown that if m is prime and if a given value of a produces the maximum period of m1, then ak will also produce the maximum period, provided that k is less than m and that k and m1 are relatively prime. Demonstrate this by using X0=1 and m=31 and producing the sequences for ak=3,32,33, and 34

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