y = log5 (log4 (2 22) ) The slope of the tangent line to the given curve at its x-intercept is: O +v6 2 In 4 In 5 O 13V6 2 In 4 In 5 O +V6 3 In 4 In 5 O 12V6 3 In 4 In 50 = 10g (logH(: 2 5 = log 3 2[. It log, b = y , Then it is written in exponential form as as = b ] from the problem, 109, (1094 ( 3 x")) = 0 It is written exponentially as, 5 - lug4 ( 3 x2) [.: on comparing with lug b = y we have a = 5, b = logy ( 3 x2 ), y = 0 . so we can write as as = b = 1094 ( 3 x 2 ) ] .'. 5 = logy ( 3 x " ) 1 = logy ( 3 x 2 ) Again using Same Method = > T.: It log b = y then a = by :4 =Here, In the question, we Need to find the a-intercept. To find the a-intercept , we Need to put you . " : y = 109 , ( 109 4 (3 2 2 3 0 = 109 5 ( 1094 ( 3 x2) ) 50 = logy N/W