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Year & life expectancy, y1950, 68.141960, 69.841970, 70.781980, 73.701990, 75.192000, 76.752010, 78.49202, 78.93 A model for the life expectancy during this period is y =

Year & life expectancy, y1950, 68.141960, 69.841970, 70.781980, 73.701990, 75.192000, 76.752010, 78.49202, 78.93

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A model for the life expectancy during this period is y = _ 68.0 + 0.33t Osts 70, 1 + 0.002t where y represents the life expectancy and t is the time in years, with t = 0 corresponding to 1950. (a) Use a graphing utility to graph the data from the table and the model in the same viewing window. How well does the model fit the data? O The model fits the data well. The model does not fit the data well. (b) Determine the life expectancy in 2010 both graphically and algebraically. (Round your answers to one decimal place.) graphically algebraically (c) Use the graph to determine the year when life expectancy was approximately 72.1. Verify your answer algebraically. (Round your answer to the nearest year (d) Identify the y-intercept of the graph of the model. (t, y) = What does it represent in the context of the problem? In the year , the life expectancy of a child (at birth) was years. (e) Do you think this model can be used to predict the life expectancy of a child 50 years from now? Explain. -Select- v . This model -Select- |be used to extrapolate data points that far into the future. Need Help? Read It

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