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Yes. Practical im new regimen will not be a factor 1: 07857 Yes. Since the agronomist has show Yes. Since the agronomist has shown e
Yes. Practical im new regimen will not be a factor 1: 07857 Yes. Since the agronomist has show Yes. Since the agronomist has shown e en produces an increase of 2 bushels per quadrat, the results have practical importance for all yield increases using the new regimen. regimen produces an increase of 2 bushels per quadrat, significant at the 1% level, higher yields are significant at the 5% level. Therefore the results have practical importance. No. The agronomist would have to show experimentally that the increase was 3 or more bushels per quadrat in order to achieve practical importance. No. Practical importance is never the same as statistical significance. 10. [-/5 Points] DETAILS MENDSTAT14 9.E.077. MY NOTES ASK YOUR TEACHER If you choose to marry, what type of wedding site will you pick? A USA Today snapshot claims that 43% of all brides-to-be choose a house of worship for their wedding site. + Brides-to-be pick their wedding sites Not sure 19% he offer place Outdoor location Club/hall/restaurant 17% By Michelle Healey and Veronica Salazar, USA TODAY In a follow-up study, a random sample of 100 brides-to-be found that 49 of those sampled had chosen or would choose a house of worship for their wedding site. Does this sample contradict the reported 43% figure? Test at the a = 0.05 level of significance. State the null and alternative hypotheses Ho: P + 0.43 versus Ha: P = 0.43 Ho: P = 0.43 versus Ha: P 0.43 Ho: P = 0.43 versus Ha: P # 0.43 Find the test statistic and rejection region. (Round your answers to two decimal places. If the test is one-tailed, enter NONE for the unused region.) test statistic Z = rejection region z> State your conclusion. s not rejected. There is insuf ntage reported by USA Today. Ho is rejected. There is ins he percentage reported by USA Today. Ho is not rejected. The eported by USA Today. Ho is rejected. There reported by USA Today. You may need to use the ap ppendix table or technology to answer this question. 11. [-/4 Points] DETAILS MENDSTAT14 10.E.001. MY NOTES ASK YOUR TEACHER Find the following t-values in Table 4 of Appendix 1. (Round your answers to three decimal places.) MAY 1 14 W X P Di MacBook Air 80 R esc F6 F9 F12 % & O delet 1 3 /L 5 6 T U O P Q W E R Y tabrejection region State your conclusion. Ho is not rejected. There is insufficient evidence to contradict the percentage reported by USA Today. Ho is rejected. There is insufficient evidence to to contradict the percentage reported by USA Today. Ho is not rejected. There is sufficient evidence to contradict the percentage reported by USA Today. Ho is rejected. There is sufficient evidence to contradict the percentage reported by USA Today. You may need to use the appropriate appendix table or technology to answer this question. 11. [-/4 Points] DETAILS MENDSTAT14 10.E.001. Find the following t-values in Table 4 of Appendix I. (Round your answers to three decimal places.) (a) to.05 for 2 of to.05 = (b) to.025 for 8 of to.025 = (c) to.10 for 16 of to.10 = (d) to.025 for 34 df to.025 12. [-/4 Points] DETAILS MENDSTAT14 10.E.019. Calculate s", the pooled estimator for of, in these cases. (Round your answers to three decimal places.) (a) n1 = 11, n2 = 4, $1 = 3.2, 52 = 4.3 $2 = ( b ) n1 = 13, n2 = 21, $1 = 18, $2 = 24 13. [-/5 Points] DETAILS MENDSTAT14 10.E.028. An experiment studied the efficacy of using 95% ethanol or 20% bleach as a disinfectant in removing bacterial and fungal contamination when culturing plant tissues. The experiment was repe plant were placed on a petri dish for each disinfectant and stored at 250C for 4 weeks. The observation reported was the number of uncontaminated eggplant cuttings after the 4-week storage Disinfectant 95% Ethanol 20% Bleach Mean 3.75 4,85 Variance 2.78091 0.17141 26,762 MAY 1 145. [-/5 Points] DETAILS MENDSTAT14 9.E.031. A random sample of n = 1,300 observations from a binomial population produced x = 357. MY NOTES (a) If your research hypothesis is that p differs from 0.3, what hypotheses should you test? Ho: p 0.3 Ho: p + 0.3 versus Ha: P = 0.3 Ho: P = 0.3 versus Ha: P 0.3 Ho: P = 0.3 versus Ha: P + 0.3 (b) Calculate the test statistic and its p-value. (Round your test statistic to two decimal places and your p-value to four decimal places.) p-value = Use the p-value to evaluate the statistical significance of the results at the 1% level. Ho is rejected since the p-value is not less than 0.01. Ho is rejected since the p-v e is less than 0.01. Ho is not rejected since the p-value is not less than 0.01. Ho is not rejected since the p-value is less than 0.01. (c) Do the data provide sufficient evidence to indicate that p is different from 0.3? Yes, the data provide sufficient evidence to indicate that p is different from 0.3. No, the data do not provide sufficient evidence to indicate that p is different from 0.3. You may need to use the appropriate appendix table or technology to answer this question. 6. [-/4 Points] DETAILS MENDSTAT14 9.E.036. MY NOTES Suppose that 20% of the fields in a given agricultural area are infested with the sweet potato whitefly. One hundred fields in this area are randomly selected, and 45 are found to be infested with whitefly. (a) Assuming that the experiment satisfies the conditions of the binomial experiment, do the data indicate that the proportion of infested fields is greater than expected? Use the p-value approach, and test using a 5% significance level. State the null and alternative hypotheses. Ho: P = 0.2 versus Ha: P # 0.2 Ho: P = 0.2 versus Ha: P > 0.2 Ho: P # 0.2 versus Ha: P = 0.2 Ho: p 0.2 Ho: P = 0.2 versus Ha: p G webassign.net Ou+O Netflix Exam 5 - TMTH 3360-2 (20948), section 2, Spring 2022 | WebAssign *Course Hero 6. [-/4 Points] DETAILS MENDSTAT14 9.E.036. MY NOTES ASK YOUR TEACHER Suppose that 20% of the fields in a given agricultural area are infested with the sweet potato whitefly. One hundred fields in this area are randomly selected, and 45 are found to be infested with whitefly. 1:08:06 (a) Assuming that the experiment satisfies the conditions of the binomial experiment, do the data indicate that the proportion of infested fields is greater than expected? Use the p-value approach, and test using a 5% significance level. State the null and alternative hypotheses Ho: p = 0.2 versus Ha: P # 0.2 Ho: P = 0.2 versus Ha: P > 0.2 Ho: p + 0.2 versus Ha: P = 0.2 Ho: p 0.2 Ho: P = 0.2 versus Ha: P 0.70 Ho: P + 0.70 versus Ha: P = 0.70 Ho: P 0.70 Find the test statistic and rejection region. (Round your answers to two decimal places. If the test is one-tailed, enter NONE for the unused region.) test statistic rejection region z> 2 0 Ho: (#1 - H2) = 0 versus Ha: (#1 - H2) 0 Ho: (H1 - H2 ) # 0 versus Ha: (#1 - H2) = 0 HO: (H1 - H2) = 0 versus Ha: (#1 - H2) + 0 State the test statistic. (Round your answer to three decimal places.) State the p-value. p-value 0.200 State the conclusion- Ho is rejected. There is insufficient evidence to conclude that there is nt difference in the mean numbers of uncontaminated eggplants for the two disinfectants used Ho is not rejected. There is i ated eggplants for the two disinfectants used. Ho is rejected. There is sufficie nificant difference in the mean numbers of uncontaminated eggplants for the two disinfectants used. Ho is not rejected. There ence to conclude that there is a significant difference in the mean numbers of uncontaminated eggplants for the two disinfectants used. You may need to use the appropriate appendix table or technology to answer this question. MY NOTES ASK YOUR TEACHER 14. [-/5 Points] 1 DETAILS MENDSTAT14 10.E.037. A naired-different se you wish to detect (12 26,762 MAY 1 14 W X P MacBook Air.. . h GO webassign.net Netflix Exam 5 - TMTH 3360-2 (20948), section 2, Spring 2022 | WebAssign Course Hero Ho is not rejecte time left. You may need to use the appropriate appendix table or technology to answer this question. 1:08:00 3. [-/5 Points] DETAILS MENDSTAT14 9.E.056 MY NOTES ASK YOUR TEACHER Acid rain, caused by the reaction of certain air pollutants with rainwater, is a growing problem in the United States. Pure rain falling through clean air registers a pH value of 5.7 (PH is a measure of acidity: 0 is acid; 14 is alkaline). A sample of n = 40 rainfalls produced PH readings with x = 3.6 and s = 0.6. Do the data provide sufficient evidence to indicate that the mean pH for rainfalls is more acidic (Ha: # 5.7 versus Ha: H 5.7 Ho: H # 5.7 versus Ha: H 2
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