Question
You and four friends decide to play Odd Person Out. In this game, the five of you each toss a fair coin. The person who
You and four friends decide to play "Odd Person Out". In this game, the five of you each toss a fair coin. The person who throws the odd outcome has to pay for the next round of drinks/coffee/kombutcha/whatever-you-all-fancy. For example, if one person flips a head while the other four flips tails, then the person who flipped the head has to pay for all five, and vice versa. Should such an outcome not occur, everyone flips again until the "odd person out" occurs. Presuming all five toss a fair coin, the random variable XX that counts the number of tosses needed to observe "odd person out" is given by
P(X=x)=(0.6875)x1(0.3125)x=1,2,3,4,P(X=x)=(0.6875)x1(0.3125)x=1,2,3,4,
It has taken 10 rounds to observe "odd person out", or X=10X=10. Did it take more trials than expected to observe "odd person out" or less? Ensure you incorporate course content in your explanation.
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