You are conducting a Goodness of Fit Chi-Squared hypothesis test (a = 0.05) for the claim that all 5 categories are equally likely to be selected. Complete the table. Category Observed Expected Frequency Frequency ((0-E) ^2/E) A 22 B 7 C 22 D 9 E 16 Round Expected values accurate to exactly 2 decimal places. Retain unrounded numbers for future calculations Round the ((0-E) ^2/E) values to 3 decimals. What is the chi-square test-statistic for this data? (Round answer to 3 decimal places, and remember to use the unrounded Pearson residuals in your calculations.) X' = What are the degrees of freedom for this test? d.f. = What is the p-value for this sample? (Round answer to 3 decimal places.) p-value =You are conducting a multinomial Goodness of Fit hypothesis test for the claim that all 5 categories are equally likely to be selected. Complete the table. Report all answers correct to three decimal places. Category Observed Expected Pearson Frequency | Frequency | Residual A 23 B 8 C 6 D 12 E 19 What is the chi-square test-statistic for this data? x2 = For significance level alpha 0.1, what is the chi-square Critical Value? Critical Value =A machine drops balls randomly into 5 bins labeled A, B, C, D, and E. If the machine is working correctly, all bins should end up with the same number of balls. Is there evidence that the machine is not working correctly? Bin Label Observed Expected Frequency Frequency Report all answers accurate to three decimal places. But retain unrounded numbers for future calculations. What is the chi-square test-statistic for this data? (Report answer accurate to three decimal places, and remember to use the unrounded Pearson residuals in your calculations.) X2: What are the degrees of freedom for this test? d. f.= What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = REST IN PEACE 2020 The numbers of COVID-19 deaths among NYC residents in April 2020 are given in the following table: Age Group Number of Deaths 0-17 7 18-44 387 45-64 1528 65-74 1689 75+ 2108 Test the hypothesis that the virus affects different age groups evenly. Use 1% level of significance. Procedure: Select an answer v Assumptions: (select everything that applies) O Normal populations All expected frequencies are 1 or greater At most 20% of the expected frequencies are less than 5 Simple random sample O Equal population standard deviations O Independent samplesBackground: Morris Saldov conducted a study in Eastern and Central Newfoundland in 1988 to examine public attitudes towards social spending. In particular, the study tried to determine if knowing someone on public assistance (yes, no) affected one's views on social spending (too little, about right, too much). The data from the study is summarized in the table below. --m "I: Source: Morris Saldov, Public Attitudes to Social Spending in Newfoundland," Canadian Review of Social Policy, 26, November 1990, pages 10-14. Directions: Conduct a chi-square test for independence to determine if the association between knowing someone on public assistance and views on social spending is statistically significant. 1. Choose the correct null and alternative hypotheses. O HO: There is no association between knowing someone on public assistance and views on social spending. Ha There is an association between knowing someone on public assistance and views on social spending. 0 H0: There is an association between knowing someone on public assistance and views on social spending. Ha There is no association between knowing someone on public assistance and views on social spending. 2. Compute the test statistic. Complete the following table of expected counts. (Round your answers to 2 decimal places). About right Too much 2. Compute the test statistic. Complete the following table of expected counts. (Round your answers to 2 decimal places). _-_ --- --- Compute the value of the test statistic. (Round your answer to 2 decimal places.) X2: 3. Compute the p-value. (Round your answer to 4 decimal places.) p-value = 4. Interpret the results of the significance test. Use a signifcance level of alpha = 0.05 O The p-value provides strong evidence against the null hypothesis. The association between knowing someone on public assistance and attitudes towards social spending is statistically significant. 0 The p-value provides little evidence against the null hypothesis. The association between knowing someone on public assistance and attitudes towards social spending is not statistically significant. 0 Question 1 v Bone mineral density and cola consumption has been recorded for a sample of patients. Let 3: represent the number of colas consumed per week and y the bone mineral density in grams per cubic centimeter. Based on the data shown below answer the questions rounding your final answers to four decimal places. (a) Create a scatter plot with linear regression line for the data. (2 points) Y = X + (b) Interpret the slope of the regression equation in a complete sentence. (2 points) 5 (c) Use the linear correlation coefficient to determine if there is correlation. (5 points) r = Is there correlation at the 0.05 level of significance? (2 points) 0 no 0 yes (d) According to the linear regression equation, the bone density of someone who drinks 23 colas per week is . (2 points) X y 0 0.98254 - 0.9764 2 0.97426 3 0.96612 4 0.95698 5 0.96184 6 0.9537 7 0.96156 8 0.95442 9 0.96028 10 0.96214 11 0.941