You have answered 0 out of 2 parts correctly. Consider the function f(x) - 1 - 8x2 on the interval [-4, 4]. (A) Find the average or mean slope of the function on this interval, i.e. f ( 4 ) - f ( -4) -32 4 - (-4) (B) By the Mean Value Theorem, we know there exists a c in the open interval (-4, 4) such that f'(c) is e mean slope. For this problem, there is only one c that works. Find it. C= 2A function f(x) and interval [a, b] are given. Check if the Mean Value Theorem can be applied to f on [a, b]. If so, find all values c in [a, b] guaranteed by the Mean Value Theorem Note, if the Mean Value Theorem does not apply, enter DNE for the c value. f(x) = 5sin x on [-1, 1] C = 0.49 (Separate multiple answers by commas.)