You hold a box of mass M = 18 kg against a steeply sloped ramp with a horizontal push P to keep it from slipping. The ramp has a slope* G = 0.607 and a coefficient of friction u = 0.332. M Here, you will determine how much you need to push in order to keep the box in place. Note: The slope of the surface is not an angle. Part 1 of 10 - Initial Assessment What is the steepest slope that you would not have to push at all? O Horizontal (G = 0) Less than half the friction coefficient ( G 58.62 N Part 2 of 10 - Collect Information Fill out the following table from the problem description. Object Property Symbol Value Box Mass M= 18 kg 18 . kg Ramp Grade G 0.607 0.607 Friction Coefficient / = 0.332 0.332Part 3 of 10 - Free Body Diagram Choose the best free body diagram from the following: NO NET ONIT Part 4 of 10 - Force Equations Write the force equations in the tangential and normal directions to the ramp using the force magnitudes (f,W, P,N) and components notation where the force does not point along an axis, e.g., the force in the x-direction is Fx. tangential: P+ +f - W f+ R - W. normal: N - W - PR N - Pr - W, Part 5 of 10 - Rewrite Components Write the components in the force equations above in terms of the slope of the ramp G, as depicted in the Figure, and the magnitude of the force (e.g., the force F would have a magnitude F). This should look like the magnitude of the force F times a fraction with two functions of G, e.g., Fx = VG F 1 -G ..although this is not the actual form of any of the answers. Make sure you have the correct signs. And a force may have a zero component in one of the two directions. *** DO NOT USE TRIG FUNCTIONS *** *** DO NOT SOLVE THE EQUATIONS OF MOTION *** * ** USE ONLY ONE MAGNITUDE AND THE SLOPE IN ANY ANSWER * * Force Tangential Norma Push P Weight W Normal Force N Nt Friction f(1) The Weight (in terms of known variables) W (2) The Frictional Force (in terms of another force) / =(1 ) W = Mg 9 = 9, 81 m / 8 2 M = 18 kg ( 2 ) f = M Nn f = MN