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You own a gas station with one gas pump. Cars arrive at your gas station following a Poisson distribution. The average inter-arrival time is

You own a gas station with one gas pump. Cars arrive at your gas station following a Poisson distribution. 

You own a gas station with one gas pump. Cars arrive at your gas station following a Poisson distribution. The average inter-arrival time is 1/3 hour. The time that the car's fueling follows the exponential distribution and the average time is 10 minutes. a) Calculate the expected number of cars in your station in the steady-state. b) For the customers, waiting time (excludes service time) costs $1 per minute. Calculate the expected waiting cost of a customer in the steady-state. c) What is the probability that a car spends more than 30 minutes in your station (includes service time) in the steady-state? d) For the customers, waiting time (excludes service time) costs $1 per minute. If you have one more gas pump, how much would be the expected waiting cost of a customer?

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a Lets define the arrival process as the number of cars arriving in a unit of time We know that the average interarrival time is 13 hour so the arriva... blur-text-image

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