You throw a nerf basketball of mass 0.002 kg into the air. At t = 0, the ball leaves your hand. Att = 0.10 s, the net force on the ba (-0.0184, -0.0224, 0) N, its velocity is (1.87, 0.84, 0) m/s, and its position is (0.325, 0.245, 0) m. (Besides the gravitational force Earth, air also exerts a force on the ball.) Part 1 What will be its position at t = 0.12 s? 7 = i i ) m Save for Later Attempts: 0 of 4 used Submit Answer Part 2 At t =0.12 s, the net force on the ball is now (-0.0126, -0.0180, 0) N. What will be its position at t = 0.14 s? r = i ) m