You will have 5 attempts for the first three parts of this problem. You will have 1 attempt for the last part of this problem. For x2 f'( ) 4x , x = . x2 +2 (x2 +2)2 f(X) = Find the x component of the critical point. (Please use exact values which might include square roots or exponentials etc. No decimals) The interval of decrease is (S, S). The interval of increase MC], [3) The critical point is a (You have one attempt for this part) O local minimum 0 local maximum O neither Check Consider a function f such that f'(x) = (x2 8w. Then: 0 f(x) has a local minimum at x = C] 0 f(x) has a local maximum at x = C] 0 f(x) is concave down over the interval ( C], S) Check