You will turn in two Geogebra worksheets (aka .ggb files).

Here is the GeoGebra website: https://www.geogebra.org/

1. Constructing the displacement vectors for the roller coaster in Problem Set 5 #1,2, and adding them to show the net displacement.

2. Illustrating a 2D projectile motion, with sliders for the time parameter, the launch angle, and the initial speed. The model should show the position vector, a point for the position, and a velocity vector attached to the position point. It should also show the nonparametric flight path.

Use Geogebra Classic 5 on 6, if online or in Windows. Net Displacement . ... .. " Veclar ? 136 ft @ 33 2 . . . .: 33 Problem Set 5 185 HQ 0 194 ft @ -H.1. Trek = ? # 1 , 2 Projectile Motion by faunch dingle hup . Initide Speed IVol meters/ second - vector megratuall . Angle D above horizontal ycomponent Vo = 1volsing . Initial velocity vxo Vyo X X component of Vo Vo = ( 131 . case , Wal song - Wol case For convenience: let Vo = / Vol, sealer muzzle speed. . Parametric equations : X = dot Voit y = yo + vyo t - Eat = 0 + vo-smo. t - 4.9 + Petition vecten T (+)= ( vocase . t, vosing ( - 4. 9 12 ) Velocity vester V (t ) = ( vocost , vosino - 9. 8+ ) speed lucti) = (vocase ) + ( Vosup - 1.8t ) = \\Voz - 2VoSOLD. 9.8+ + (9.8t ) Twhy ? Non parametric Flight Path: Relate y directly to x without t: X = Voceset => + = x Vo corp , substitute: y = vosup. t - 4.9t = voSug. X - 4.9 x2 y = tang . x - 4.9 V 2 ( parabola ) Not required for PHS241 - Bonus Round - Acceleration act ) = ( 6 , - 9.8 ) mysz. - vectordot product a. V Tangential acceleration : V = - 9.8 Vosing + 9. 8 + vocapt , vosnof - 9,8t ) VJ - 2 Vosing. 1.8 + +9.82t ? Vit ) VOV = 1012 Normal acceleration = a- V = eww let geagebra do it(9 Problem Set 5: Attempt review , Personal , Mutmsort Edge 3. El X ll httpsif/Ugfmroom53.net/mod/quiz/review.plrp7attempt=35366i&cmid=694153 P. ' A Not answered Marked out of 3.00 \\3 Flag question I At what angle relative to its starting point did the roller coaster end up? To solve this problem: 1. Divide the ycomponent of the overall displacement by its xcomponent; 2. Find the arctan of your result in step 1; 3. Adjust the calculated angle by 1800 (if needed) based on the value of the x- and y- components of the overall displacement. Answer: X You did not give the correct unit. 1 1:33 AM 9/29/2023 57\"; A C; :IX [1 Sunny : Problem Set 5: Attempt review - Personal - Microsoft Edge - 0 X @ https://ugf.mrooms3.net/mod/quiz/review.php?attempt=353661&cmid=694153 Question 1 Correct Mark 4.00 out of 4.00 Flag question A roller coaster moves 185 ft horizontally and then rises 136 ft at an angle of 33.0 above the horizontal. Next, it travels 144 ft at an angle of 41.10 below the horizontal. Find the roller coaster's straight-line distance from its starting point at the end of this movement. To solve this problem: 1. Find the x- and y-components of each displacement; 2. Add the x-components together to get the x-component of the overall displacement; 3. Add the y-components together to get the y-component of the overall displacement; 4. Find the square root of the sum of the squares of the components of the overall displacement. Answer: 408.091 ft GBP/USD Q Search 9:20 AM -0.61% 10/2/2023