Your friend Nalini Iyer comes across the device shown in figure 5 GO + V GE C + ex 10x/2.303 e24 2.5 x 100 e25 7 x 100 e26 17.5 x 10 V Figure 5: Nonlinear Device OE CE (a) (10 points) She characterizes the device and finds the following equation describes the current I with I, = 1 fA Ic = IseVGE/KT (1-e-qVCE/KT) (1) = in thegraph provided, plot the Ic vs. curve for the following values of VGE 24kT/q, 25kT/q, 26kT/q for VCE ranging from 0 100kT/q given the device is operating at room temperature for which kT/q 25 mV. You may want to use a minor grid of 5kT/q.Hint: See how the exponential term dependent on VCE compares to 1, what happens if VCE is very small (smells like a taylors expansion!)? What happens when VCE is very large?. Some useful approximations to help you with calculations is given in Table 1 Table 1: Some Useful Approximations ex 10y = 0 1 2 3 4 5 6 0 7 8 9 10 11 12 13 14 15 16 17 18 19 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 Figure 6: Nonlinear Device Characteristics 28