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Your video analysis of the motion of a marble gives it position in frame 23 as = (x23, 923) (0.134 m, 0.120 m) and

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Your video analysis of the motion of a marble gives it position in frame 23 as = (x23, 923) (0.134 m, 0.120 m) and its position in frame 24 as (x24, 24) = (0.102 m, 0.112 m). You estimate that you can measure the x and y positions with uncertainty 0.003 m. The frame rate of the video is 30 frames/s, which means the time interval between frames is At = 0.033333 s. The uncertainty of the frame rate of a video camera is VERY small. For the sake of this problem, use (At) = 1 10 6 s. The mass of the marble is (2.031 0.001) 10 2 kg. Question 6 Find value of the x-component of the marble's velocity v = uncertainty. O (-0.4020.004) m/s (-0.9600.127) m/s (4.02 0.01) m/s O (-1.00.1) m/s (-0.9600.004) m/s 2.5 pts Xi+1 - xi At and its

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