yow have $3$ CSTRs in series where the first tark feeds into the next.

The concentrations $(x)$ of each CSTR are defined by the transer equations:

$G_3(s)=\frac{x_1(s)}{x_3(s)}=\frac{1}{rs+1}$

$G_2(s)=\frac{x_3(s)}{x_3(s)}=\frac{1}{rs+1}$

$G_y(s)=\frac{x_{na}(s)}{x_2(s)}=\frac{1}{r+1}$

Find an equation that successfully relates the input concentration sit to the final

cutput concentration $x3$ for a step inpu: for $$ of $0\mathrm{.}1$ male fraction. is

$x_i(s)=\frac{M}{s}$

Where $M=0\mathrm{.}1$mol fraction. The initial oonditions of the input and cutput cancentrations

are the same and at steady state, i$.$e$.(0)=x3(0)=0\mathrm{.}5.$ Take $r$ as $3$min.

Use Excel to graphically compare the time response of the $3$ CSTRs in series with

one large CSTR with $3$ times the volume of one of the smalier CSTRs in series. $($l$.$e$.$ the tatal

walume $($and residence time$)$ of the large CSTR $=$ the sotal volume $($and residence time$)$ of

the $3$ CSTRs in series$).$ Use the same initial conditions and step size as previously stated. The

transfer equation for the Large CSTR can be given as:

$G(s)=\frac{x_{\text{o}\text{r}\text{d}}(s)}{x_x(s)}=\frac{1}{3rs+1}$

Your plots $x($or time axis$)$ should be long enough to where the time response decays, about