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yz ) 1 + xyj + x2z2 k, is the cone x = vy2 + z2, 0 z + x 2 y j + x2z2k
yz" ) 1 + xyj + x2z2 k, is the cone x = vy2 + z2, 0
z + x 2 y j + x2z2k is the cone x y 2 + z2 , 0 x 2, oriented in the "ieection of the positive x-axis iF(x, y, z) xyz i + xyj + x2yz k, S consists of the top and the four sides (but not the bottom) of the cube with vertices ( l, l, l), oriented outward S is the half of the ellipsoid 4x2 + yi + 4z2 4 that lies to the right of the xz-plane, oriented in the direction of the positive y-axis 710 Use Stokes' Theorem to evaluate Sc F dr. In each case C is oriented counterclockwise as viewed from above. F(x, y, z) = (x + y2)i + (y + z2)j + (z + x2)k, C is the triangle with vertices (l, 0, 0), (0, l, 0), and (0, 0,
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