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Z = 2.326411417 P = .0199965665 x = 45.25 n = 62 Part 1 of 5 V What are the null and alternate hypotheses? Ho:
Z = 2.326411417 P = .0199965665 x = 45.25 n = 62 Part 1 of 5 V What are the null and alternate hypotheses? Ho: H = 42 HOW # 42 Part: 1 / 5 Part 2 of 5 What is the value of the test statistic? Enter the value to the full accuracy shown (do not round). Z(a) State the appropriate null and alternate hypotheses. (b) Compute the P-value. (c) Determine whether to reject Ho. Use the a = 0.01 level of significance. (d) State a conclusion.Weight loss: In a study to determine whether counseling could help people lose weight, a sample of people experienced a group-based behavioral intervention, which involved weekly meetings with a trained interventionist for a period of six months. The following data are the numbers of pounds lost for 14 people. Assume the population is approximately normal. Perform a hypothesis test to determine whether the mean weight loss is greater than 17 pounds. Use the a = 0.01 level of significance and the P-value method with the TI-84 Plus calculator. 20.8 27.0 6.1 22.5 19.5 11.2 16.0 19.5 35.9 32.3 10.7 34.3 21.9 17.7 Send data to Excel Part: 0 / 4 Part 1 of 4 (a) State the appropriate null and alternate hypotheses. Ho: H: This hypothesis test is a (Choose one) test. Skip Part Check Answer Save For Later Submit Assignmer
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