Zoologists studied the characteristics of the burrow systems of a subterranean rodent. A sample of 51 burrows had their depths, in centimeters, recorded in the following table. Complete parts (a) through (c) below using technology. a Click the icon to View a table of depths of subterranean burrow systems. 3. Obtain a normal probability plot, boxplot, histogram. and stem-and-leaf diagram of the data. Choose the correct normal probability plot below. O A- O B. O c. o o. 3 a 3 a 3' a 3' a v w s ' e Q Q Q Q (Eu 3)) (Eu 3)) (En m) E\" ) 2s _ :4 2s a g a g a , , o ,3 g: Depth (cm) Depth (cm) Depth (cm) Depth (cm) \fb. Based on your results from part (a), can you reasonably apply the t-interval procedure to the data? Explain your reasoning. Select all that apply. [I A. The boxplot shows potential outliers, so it is not appropriate to apply the t-interval prooedure. I] B. The sample size is large enough that the t-interval prooedure will be robust to moderate violations of the normality assumption. [I C. The normal probability plot is not approximately linear, so the normality assumption is not satised. I] D. The histogram shows potential outliers, so it is not appropriate to apply the tinterval procedure. [I E. The normal probability plot is approximately linear, and the boxplot, histogram, and stemplot do not show any outliers. The assumptions are satised. c. Find and interpret a 99% condence interval for the mean depth of all subterranean rodent burrows. The 99% condence interval for u is from to (Round to three decimal places as needed.) Interpret the condence interval. Choose the correct answer below and ll in the answer boxes to complete your choice. (Round to three decimal places as needed.) 0 A- We can be 99% condent that the mean depth of all subterranean rodent burrows is somewhere between 0 B- 99% of all subterranean rodent burrows have a depth somewhere between cm and cm. cm and ClTI. stion: 1 point{5) p055 Table of Burrow Depths the following table. Co Depths (cm) E 15.7 13.6 19.1 15.4 17.7 14.2 18.3 12.8 12.7 18.8 18.5 12.9 13.8 16.9 13.8 15.6 13.2 16.3 14.5 14.2 17.8 12.5 14.7 13.8 11.0 12.8 14.0 12.2 11.3 16.1 17.8 16.3 11.5 16.7 17.9 15.6 16.5 8.0 16.3 Depth (cm) 16.4 19.5 9.6 ' Normal score on. C) Time Rem.- \fThe graph to the right portrays the decision criterion for a hypothesis test for a population mean it. The null hypothesis for the test is H0: [1 = p0. The Do not Q curve in the graph is the normal curve for the test statistic under the assumption that the null hypothesis is true. Complete parts (a) through (f) below. "919d 4.405 0 1.405 c. Determine the critical value(s). z= 1.405, 1.405 (Type integers or decimals. Do not round. Use a comma to separate answers as needed.) d. Determine the signicance level. a: (Type an integer or a decimal. Do not round.) Determine the critical value(s) for a one-mean z-test. Draw a graph that illustrates your answer. A right-tailed test with r: = 0.01. Click here to view Page 1 of the table of areas under the standard normal curve. Click here to View Page 2 of the table of areas under the standard normal curve. The critical value(s) is (are) . (Round to two decimal places as needed. Use a comma to separate answers as needed.) Choose the correct graph of the hypothesis test below. B. Qc. Do not Reject Q . Do not Q c. Remove the outliers (if any) from the data and then repeal part (a). Identify the potential outliers. Choose the correct answer below and ll in the answer box, if necessary, to complete your choice. O A- The potential outlier(s) is(are) _ (Type an integer or a decimal. Do not round. Use a comma to separate answers as needed.) O B. There are no potential outliers in the data. State the hypotheses for the one-mean z-test. H041 V % Ha: p V % (Type integers or decimals. Do not round.) Compute the value of the test statistic. z: (Round to two decimal places as needed.) Determine the Pvalue. P: (Round to three decimal places as needed.) V the null hypothesis. At the 1% signicance level, the data "he sample size is V V d. Comment on the advisability of using the z-test here. and the plots indicate that the data are sufcient evidence to conclude that the mean net percentage gain for jobs is V 0.2% per quarter. V and at least one outlier. Therefore, using the one-sample z-test for the mean is \fA researcher examined gross job gains and losses as a percentage of the average of previous and current employment gures. Asimple random sample of 20 quarters provided the net percentage gains (losses are negative gains) forjobs as shown in the accompanying table. Complete parts (a) through (d) below. Click here to view the net percentage job gain data. a. Decide whether, on average, the net percentage gain forjobs exceeds 0.2. Assume a population standard deviation of 0.41. Apply the one-mean z-test with a 1% signicance level. ' State the hypotheses for the one-mean z-test. I H0: p. V % Ha: I1 V % (Type integers or decimals. Do not round.) Compute the value of the test statistic. z = (Round to two decimal places as needed.) Determine the Pvalue. p = (Round to three decimal places as needed.) V