Derive (15-44) and use it to solve the following problem. Sulfate ion is to be removed from

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Derive (15-44) and use it to solve the following problem. Sulfate ion is to be removed from 60 L of water by exchanging it with chloride ion on 1 L of a strong-base resin with relative molar selectivities as listed in Table 15.6 and an ion-exchange capacity of 1.2 eq/L of resin. The water to be treated has a sulfate-ion concentration of 0.018 eq/L and a chloride-ion concentration of 0.002 eq/L. Following the attainment of equilibrium ion exchange, the treated water will be removed and the resin will be regenerated with 30 L of 10 wt% aqueous NaCl. 

(a) Write the ion-exchange reaction. 

(b) Determine the value of KSO2-; Cl-

(c) Calculate equilibrium concentrations cSO2-, cCI, qSO2-4, and qCI- in eq/L for the initial ionexchange step. 

(d) Calculate the concentration of Clin eq/L for the regenerating solution. 

(e) Calculate cSO2-, and qClupon reaching equilibrium in the regeneration step. 

(f) Are the separations sufficiently selective?

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Separation Process Principles Chemical And Biochemical Principles

ISBN: 9780470481837

3rd Edition

Authors: By J. D. Seader, Ernest J. Henley, D. Keith Roper

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