Derive (15-44) and use it to solve the following problem. Sulfate ion is to be removed from
Question:
Derive (15-44) and use it to solve the following problem. Sulfate ion is to be removed from 60 L of water by exchanging it with chloride ion on 1 L of a strong-base resin with relative molar selectivities as listed in Table 15.6 and an ion-exchange capacity of 1.2 eq/L of resin. The water to be treated has a sulfate-ion concentration of 0.018 eq/L and a chloride-ion concentration of 0.002 eq/L. Following the attainment of equilibrium ion exchange, the treated water will be removed and the resin will be regenerated with 30 L of 10 wt% aqueous NaCl.
(a) Write the ion-exchange reaction.
(b) Determine the value of KSO2-4 ; Cl-
(c) Calculate equilibrium concentrations cSO2-4 , cCI- , qSO2-4, and qCI- in eq/L for the initial ionexchange step.
(d) Calculate the concentration of Cl- in eq/L for the regenerating solution.
(e) Calculate cSO2-4 , and qCl- upon reaching equilibrium in the regeneration step.
(f) Are the separations sufficiently selective?
Step by Step Answer:
Separation Process Principles Chemical And Biochemical Principles
ISBN: 9780470481837
3rd Edition
Authors: By J. D. Seader, Ernest J. Henley, D. Keith Roper