An AISI 1018 steel has a yield strength, S y = 295 MPa. Using the distortion-energy theory

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An AISI 1018 steel has a yield strength, S_y = 295 MPa. Using the distortion-energy theory for the given state of plane stress,

(a) Determine the factor of safety,

(b) Plot the failure locus, the load line, and estimate the factor of safety by graphical measurement.

0x (MPa) Ty (MPa) Txy (MPa) - 30 -65 40

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Shigley's Mechanical Engineering Design

ISBN: 9780073398204

10th Edition

Authors: Richard Budynas, Keith Nisbett

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Question Posted: Oct 28, 2020 07:21 AM

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An AISI 1018 steel has a yield strength, S y = 295 MPa. Using the distortion-energy theory for the given state of plane stress, (a) Determine the factor of safety, (b) Plot the failure locus, the...
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An AISI 1018 steel has a yield strength, S y = 295 MPa. Using the distortion-energy theory

Question:

0x (MPa) Ty (MPa) Txy (MPa) - 30 -65 40

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a b Sy 295...View the full answer

Shigley's Mechanical Engineering Design

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