Consider the triangular train of pulses x(t) in Figure 1.23. (a) Carefully plot the derivative of x(t),
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(a) Carefully plot the derivative of x(t), y(t) = dx(t)/dt.
(b) Can you compute
![| [(x(t) – 0.5]dt? z(t) =](https://dsd5zvtm8ll6.cloudfront.net/si.question.images/images/question_images/1544/8/8/9/2255c152389820221544871802415.jpg){kind=small}
If so, what is it equal to? If not, explain why not.
(c) Is x(t) a finite energy signal? how about y(t)?
Figure 1.23:
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a The derivative signal yt dxtdt is a train of rectan...View the full answer
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