Show that if the algorithm of Theorem 31 produces a deterministic PDA, then the language has only
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Show that if the algorithm of Theorem 31 produces a deterministic PDA, then the language has only one word in it.
We shall now use the algorithm of Theorem 31 to tum this machine back into a CFG. First, we must put this PDA into conversion form:
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START POP PUSH $ PUSH S PUSH $ PUSH A PUSH N POP POP PUSH S PUSH S A POP READ, POP HERE POP PUSH A PUSH A POP POP PUSH $ H READ, POP ACCEPT
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The algorithm described in Theorem 31 likely converts a contextfree grammar CFG into a deterministic ...View the full answer
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