Show that the mean of a hypergeometric random variable Y is = nr/N. Show that and

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Show that the mean of a hypergeometric random variable Y is μ = nr/N. Show that

and then use the fact that

is the hypergeometric probability distribution for Z = (Y - 1), where Z is the number of S’s in (n - 1) trials, with a total of (r - 1) S’s in (N - 1) elements.]

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Statistics For Engineering And The Sciences

ISBN: 9781498728850

6th Edition

Authors: William M. Mendenhall, Terry L. Sincich

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Question Posted: Apr 08, 2021 05:19 AM

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Show that the mean of a hypergeometric random variable Y is = nr/N. Show that and

Question:

(N 1-(r-1)) - 1- (у — 1)/ nr N N. N-

Step by Step Answer:

To show that the mean of a hypergeometric random variable Y is nrN we can use the definition of the mean for a discrete random variable The hypergeome...View the full answer

Statistics For Engineering And The Sciences

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