840 A current of it = 100 cos 10 kt 45mA is applied across a parallel

8–40 A current of iðtÞ = 100 cos ð10 kt – 45ÞmA is applied across a parallel connection of a 1:5-kΩ resistor, a 150-mH inductor, and a 0:0667-μF capacitor. Use current division to find the steady-state currents iCðtÞ, iLðtÞ, and iRðtÞ through each of the three elements. Find the phasor voltage across the parallel connection. Draw a phasor diagram showing V, IC, IL, and IR. Comment on the results.