Consider a car of similar characteristics and the same design requirements as those used for the open-loop system, i.e., \(m=1,000 \mathrm{~kg}\) and \(b=50 \mathrm{~N} \mathrm{sec} / \mathrm{m}\), where the reference (input) speed of interest is \(10 \mathrm{~m} / \mathrm{sec}\). The step function in MATLAB calculates the response to a step input \((1 \mathrm{~m} / \mathrm{sec})\). Hence, matrix \(\boldsymbol{B}\) will correspondingly have to be multiplied by the magnitude reference speed \(10 \mathrm{~m} / \mathrm{sec}\). The MATLAB command is the same as that in the open-loop system, but the system matrices are different, as shown below