Question: Show that a charged particle moving in the plane perpendicular to a constant magnetic field (eq. (19.29) moves in a circle with Br = mv/q.

Show that a charged particle moving in the plane perpendicular to a constant magnetic field (eq. (19.29)

F = qE + qv x B +qv

moves in a circle with Br = mv/q. What is the radius of the circle for an electron with energy 15 keV in a 10 Tesla magnetic field (typical of ITER)? What is the radius for a proton?

F = qE + qv x B +qv

Step by Step Solution

3.27 Rating (173 Votes )

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock

The magnetic force on a charged particle is given by eq 345 Since the force ... View full answer

blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related The Physics Energy Questions!