=+25. Example 10.5.3 relies on some unsubstantiated claims. Prove that: (a) (1 x)k ekx for

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=+25. Example 10.5.3 relies on some unsubstantiated claims. Prove that:

(a) (1 − x)k ≤ e−kx for x ∈ (0, 1) and k > 0,

(b) |Dn − Xn−1| ≤ 2

√

2, and

(c) 1 + ··· + 1 n−1 ≤ ln n + 1

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Applied Probability

ISBN: 9781441971647

2nd Edition

Authors: Kenneth Lange

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Question Posted: Nov 01, 2024 04:00 AM

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=+25. Example 10.5.3 relies on some unsubstantiated claims. Prove that: (a) (1 x)k ekx for x (0, 1) and k > 0, (b) |Dn Xn1| 2 2, and (c) 1 + + 1 n1 ln n + 1
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=+25. Example 10.5.3 relies on some unsubstantiated claims. Prove that: (a) (1 x)k ekx for

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Applied Probability

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