Let {X(t), < t < } be a weakly stationary process having covariance function RX (s)
Question:
Let {X(t), −∞ < t < ∞} be a weakly stationary process having covariance function RX (s) = Cov[X(t), X(t + s)].
(a) Show that Var(X(t + s) − X(t)) = 2RX (0) − 2RX (t)
(b) If Y (t) = X(t + 1) − X(t) show that {Y (t), −∞ < t < ∞} is also weakly stationary having a covariance function RY (s) = Cov[Y (t), Y (t + s)] that satisfies RY (s) = 2RX (s) − RX (s − 1) − RX (s + 1)
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