=+N pp 2(2t + 1)/n + 2pt . (Hint: b1 = p2t + 2tp2t (1

=+β∈Nα pαpβ ≤ λ2(2t + 1)/n + 2λpt

. (Hint:

b1 = p2t + 2tp2t

(1 − p)

+ [2nt − t 2 + n − 3t − 1]p2t

(1 − p)

2 exactly. Note that the pairs α and β entering into the double sum for b1 are drawn from the integer lattice points {(i, j):1 ≤ i, j ≤ n}. An upper-left triangle and a lower-right triangle of lattice points from this square do not qualify for the double sum defining b1. The term p2t in b1 corresponds to the lattice point (1, 1).)