Normal distribution and combinatorial runs.10 In II, (11.19) we found that in an arrangement of n alphas and m betas the probability of having exactly k runs of alphas is (7.6) k n- m+ 'n *-=)(*)(*). )/(" + "). k n Let nco, m so that (7.4) holds. For fixed a > the probability that the number of alpha runs lies between npq + apqn and npq + Bpqn tends to N() N(). -