Question: Suppose we have two four-point sequences x[n] and h[n] as follows: x[n] = cos (n/2). n = 0, 1, 2, 3. h[n] = 2 n
Suppose we have two four-point sequences x[n] and h[n] as follows:
x[n] = cos (πn/2). n = 0, 1, 2, 3.
h[n] = 2n, n = 0, 1, 2, 3.
(a) Calculate the four-point DFT X[k].
(b) Calculate the four-point DFT H[k].
(c) Calculate y[n] = x[n] (4) h[n] by doing the circular convolution directly.
(d) Calculate y[n] of part (c) by multiplying the DFTs of x[n] and h[n] and performing an inverse DFT.
Step by Step Solution
3.46 Rating (169 Votes )
There are 3 Steps involved in it
a b c Remember circulart convolution equals linear convolution plus aliasing We need N 4 ... View full answer
Get step-by-step solutions from verified subject matter experts
Document Format (1 attachment)
30-E-T-E-D-S-P (339).docx
120 KBs Word File
