Suppose we have two four-point sequences x[n] and h[n] as follows: x[n] = cos (n/2). n =
Question:
Suppose we have two four-point sequences x[n] and h[n] as follows:
x[n] = cos (πn/2). n = 0, 1, 2, 3.
h[n] = 2n, n = 0, 1, 2, 3.
(a) Calculate the four-point DFT X[k].
(b) Calculate the four-point DFT H[k].
(c) Calculate y[n] = x[n] (4) h[n] by doing the circular convolution directly.
(d) Calculate y[n] of part (c) by multiplying the DFTs of x[n] and h[n] and performing an inverse DFT.
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a b c Remember circulart convolution equals linear convolution plus aliasing We need N 4 ...View the full answer
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Related Book For
Discrete Time Signal Processing
ISBN: 978-0137549207
2nd Edition
Authors: Alan V. Oppenheim, Rolan W. Schafer
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