The Fibonacci sequence also satisfies the equation Fn n = 1/5[(1 +5/2)n (1 5/2)n]. a. Write
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Fn ≡ n = 1/√5[(1 +√5/2)n −(1 −√5/2)n].
a. Write a Maple procedure to calculate F100.
b. Use Maple with the default value of Digits followed by evalf to calculate 100.
c. Why is the result from part (a) more accurate than the result from part (b)?
d. Why is the result from part (b) obtained more rapidly than the result from part (a)?
e. What results when you use the command simplify instead of evalf to compute 100?
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