Question: The following data were collected in two studies of the reaction 2A + B C + D where In experiment 1, [B] 0 = 5.0
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In experiment 1, [B] 0 = 5.0 M. In experiment 2, [B] 0 = 10.0 M.
a. Why is [B] much greater than [A]?
b. Give the rate law and value for k for this reaction.
c. Which of the following mechanisms could be correct for this reaction? Justify your choice.
i. A + B E (fast equilibrium)
E + B C + D (slow)
ii. A + B E (fast equilibrium)
E + A C + D (slow)
iii. A + A E (slow)
E + B C + D (fast)
Rate-_ xperiment 1 (M)X 10 Experiment 2 AJ (M)x 10-2 Time (s 20. 40. 60. 80. 100. 120. 10.0 6.67 5,00 4.00 3.33 2.86 2.50 10.0 5.00 3.33 2.50 2.00 1.67 1.43
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a B A so B can be considered constant over the experiments This gives us a pseudoorder ratelaw equat... View full answer
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