The force F = (xi + yj + zk) / (x2 + y2 + z2)3/2 acts on

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The force F = (xi + yj + zk) / (x2 + y2 + z2)3/2 acts on the particle P(x,y,z) which moves in space.

(a) Using the relation derived in Prob. 13.77, prove that F is a conservative force.

(b) Determine the potential function V(x,y,z)associated with F.

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Vector Mechanics for Engineers Statics and Dynamics

ISBN: 978-0073212227

8th Edition

Authors: Ferdinand Beer, E. Russell Johnston, Jr., Elliot Eisenberg, William Clausen, David Mazurek, Phillip Cornwell

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Question Posted: Oct 19, 2010 02:36 AM

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The force F = (xi + yj + zk) / (x2 + y2 + z2)3/2 acts on

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a Thus Fx Similarly integrating DF 11 11 X x y2 z27 and Fx x32x x y ...View the full answer

Vector Mechanics for Engineers Statics and Dynamics

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