Question: The force F acting on a body with mass m and velocity is the rate of change of momentum: F = (d/dt)(m), If m is

The force F acting on a body with mass m and velocity is the rate of change of momentum: F = (d/dt)(m), If m is constant, this becomes F = ma, where a = dv/dt is the acceleration. But in the theory of relativity the mass of a particle varies with as follows: m = m0 / √1 - v2 / c2, where m0 is the mass of the particle at rest and is the speed of light. Show that
F = m0a/(1 - v2/c2)3/2

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