The laminar-pipe-flow example of Prob. 1.14 leads to a capillary viscometer [27], using the formula = ro

Question:

The laminar-pipe-flow example of Prob. 1.14 leads to a capillary viscometer [27], using the formula μ = π ro 4Δp/ (8LQ). Given ro = 2 mm and L = 25 cm. The data are
Q, m3/hr: 0.36 0.72 1.08 1.44 1.80
Δp, kPa: 159 318 477 1274 1851
Estimate the fluid viscosity. What is wrong with the last two data points?