The relative conductivity of a semiconductor device is determined by the amount of impurity doped into the
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[SAS explicitly tests H0: μ = 0, so to test H0: μ = .60, the null value .60 must be subtracted from each xi; the reported mean is then the average of the (xi - .60) values. Also, SAS's P-value is always for a two-tailed test.] What would be concluded for a significance level of .01? .05? .10?
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Probability And Statistics For Engineering And The Sciences
ISBN: 9781305251809
9th Edition
Authors: Jay L. Devore
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