The standard heat of combustion (Hc) of liquid 2.3,3-trimethylpentane [C8H18] is reported in a table of physical properties to be 4850 kJ/mol. A footnote indicates

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The standard heat of combustion (ΔH˚c) of liquid 2.3,3-trimethylpentane [C8H18] is reported in a table of physical properties to be —4850 kJ/mol. A footnote indicates that the reference temperature for the reported value is 25°C and the presumed combustion products are CO2 (g) and H2O (g).

(a) In your own words, briefly explain what all that means.

(b) There is some question about the accuracy of the reported value, and you have been asked to determine the heat of combustion experimentally. You burn 2.010 grams of the hydrocarbon with pure oxygen in a constant-volume calorimeter and find that the net heat released when the reactants and products [CO2 (g) and H2O (g)] are all at 25°C is sufficient to raise the temperature of 1.00 kg of liquid water by 21.34°C. Write an energy balance to show that the heat released in the calorimeter equals nC8H18 ΔU˚c. and calculate U: (kJ/mol). Then calculate ΔH˚c. By what percentage of the measured value does the tabulated value differ from the measured one?

(c) Use the result of part (b) to estimate for 2,3,3-trirnethyipentane. Why would the heat of formation of 2, 3, 3-trimethylpentane probably be determined this way rather than directly from the formation reaction?

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a b 2g 8COg 9HOg AH 4850 kJmol C3H18 1 0 g When 1 gmole of CHs1 and 125 gmoles ... View full answer

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