The velocity of a 3.00 kg particle is given by v = (8.00ti + 3.00t2j) m/s, with

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The velocity of a 3.00 kg particle is given by v = (8.00ti + 3.00t2j) m/s, with time t in seconds. At the instant the net force on the particle has a magnitude of 35.0 N, what is the direction (relative to the positive direction of the x axis) of

(a) The net force and

(b) The particle's direction of travel?

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Fundamentals of Physics

ISBN: 978-0471758013

8th Extended edition

Authors: Jearl Walker, Halliday Resnick

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Question Posted: Jan 08, 2011 02:33 AM

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The velocity of a 3.00 kg particle is given by v = (8.00ti + 3.00t2j) m/s, with

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Fundamentals of Physics

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