Using Stirlings formula (see Exercise 1.6) to approximate 2n! and n!, show that 2n 22n ~ 1

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Using Stirling’s formula (see Exercise 1.6) to approximate 2n! and n!, show that

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John E Freunds Mathematical Statistics With Applications

ISBN: 9780134995373

8th Edition

Authors: Irwin Miller, Marylees Miller

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Question Posted: Nov 04, 2015 02:47 AM

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Using Stirlings formula (see Exercise 1.6) to approximate 2n! and n!, show that 2n 22n ~ 1

Question:

2n 22nㅡㅡㅡ ~ 1

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John E Freunds Mathematical Statistics With Applications

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