All Matches
Solution Library
Expert Answer
Textbooks
Search Textbook questions, tutors and Books
Oops, something went wrong!
Change your search query and then try again
Toggle navigation
FREE Trial
S
Books
FREE
Tutors
Study Help
Expert Questions
Accounting
General Management
Mathematics
Finance
Organizational Behaviour
Law
Physics
Operating System
Management Leadership
Sociology
Programming
Marketing
Database
Computer Network
Economics
Textbooks Solutions
Accounting
Managerial Accounting
Management Leadership
Cost Accounting
Statistics
Business Law
Corporate Finance
Finance
Economics
Auditing
Ask a Question
Search
Search
Sign In
Register
study help
business
financial accounting information for decisions
Questions and Answers of
Financial Accounting Information For Decisions
Solve.a. log5 (x + 8) + log5 (x + 2) = log5 20xb. log3 x + log3 (x – 2) = log3 15c. 2 log4 x – log4 (x + 3) = 1d. lg x + lg(x + 1) = lg 20e. log3 x + log3(2x – 5) = 1f. 3 + 2 log2 x = log2 (14x
Solve, giving your answers correct to 3 sf.a. 2x+2 – 2x = 4b. 2x+1 – 2x-1 – 8 = 0c. 3x+1 – 8(3x-1) – 5 = 0d. 2x+2 – 2x-3 = 12e. 5x – 5x+2 + 125 = 0
a. Given that logp x = 20 and logp y = 5, find logy x.b. Given that logp X = 15 and logp Y = 6, find the value of logx Y.
Solve.a. eln x = 7b. ln ex = 2.5c. eln x = 36d. e-ln x = 20
Solve each of these equations, giving your answers correct to 3 sf.a. lg x = 5.1b. lg x = 3.16c. lg x = 2.16d. lg x = - 0.3e. lg x = - 1.5f. lg x = - 2.84
Solve.a. logx 64 – logx 4 = 1b. logx 16 + logx 4 = 3c. logx 4 – 2logx 3 = 2d. logx 15 = 2 + logx 5
Without using a calculator, find the value ofa. lg 10,000b. lg 0.01c. lg √10d. lg (3√10)e. lg (10√10)f. lg (1000/√10).
Find the value ofa. log4 16b. log3 81c. log4 64d. log2 0.25e. log3 243f. log2 (8√2)g. log5 (25√5)h. log2 (1/√8)i. log64 8j. log7 (√7/7)k. log5 3√5l. log3 1/√3
A species of fish is introduced to a lake.The population, N, of this species of fish after t weeks is given by the formulaN = 500 e-0.3t.a. Find the initial population of these fish.b. Estimate the
F(x) = ex for x ∈ R. g(x) = ln 5x for x > 0a. Findi. fg(x)ii. gf(x).b. Solve g(x) = 3f-1(x).
Given that logP X = 5 and logP Y = 2y finda. logP X2,b. logP 1/X,c. logXY P.
a. Express 16 and 0.25 as powers of 2.b. Hence, simplify log3 16/log3 0.25.
Use the substitution y = 3x to solve the equation 32x + 2 = 5(3x).
Evaluate logp 2 × log8p.
Solve, giving your answers correct to 3 sf.a. ex = 70b. e2x = 28c. ex+1 = 16d. e2x-1 = 5
Simplify.a. logx x2b. logx 3√xc. logx (x√x)d. logx 1/x2e. logx (1/x2)3f. logx (√x7)g. logx (x/3√x)h. logx (x√x/3√x)
The value, $V, of a house n years after it was built is given by the formulaV = 250,000 ean.When n = 3, V = 350,000.a. Find the initial value of this house.b. Find the value of a.c. Estimate the
F(x) = e3x for x ∈ R. g(x) = ln x for x > 0a. Findi. fg(x)ii. gf(x).b. Solve f(x) = 2g-1(x).
Solve.a. log9 3 + log9(x + 4) = log5 25b. 2 log4 2 + log7(2x + 3) = log3 27
a. Given that log4 x = 1/2, find the value of x.b. Solve 2 log4 y – log4(5y – 12) = ½,
Simplify.a. log7 4 / log7 2b. log7 27 / log7 3c. log3 64 / log3 0.25d. log5 100 / log5 0.01
Solve.a. (log5 x2) – 3log5(x) + 2 = 0b. (log5 x)2 – log5(x2) = 15c. (log5 x)2 – log5(x3) = 18d. 2(log2 x)2 + 5log2 (x2) = 72
Solve, giving your answer correct to 3 sf. za. 32x – 6 × 3x + 5 = 0b. 42x – 6 × 4x – 7 = 0c. 22x – 2x – 20 = 0d. 52x – 2(5x) – 3 = 0
Use the substitution u = 5x to solve the equation 52x – 2(5x+1) + 21 = 0.
Solve, giving your answers in terms of natural logarithms.a. ex = 7b. 2ex + 1 = 7c. e2x-5 = 3d. 1/2 e3x-1 = 4
Solve.a. log3 (log2 x) = 1b. log2 (log5 x) = 2
F(x) = e2x for x ∈ R. g(x) = ln(2x + 1) for x > - ½a. Find fg(x).b. Solve f(x) = 8g-1(x).
The area, A cm2, of a patch of mould is measured daily.The area, n days after the measurements started, is given by the formulaA = A0bn.When n = 2, A = 1.8 and when n = 3, A = 2.4.a. Find the value
Solve the equation 32x = 1000, giving your answer to 2 decimal places.
Given that u = log5 x, find, in simplest form in terms of u.a. xb. log5 (x/25)c. log5 (5√x)d. log5 (x√x / 125).
Solve the simultaneous equations.a. xy = 64logx y = 2b. 2x = 4y2lg y = lg x + lg 5c. log4(x + y) = 2 log4 xlog4 y = log4 3 + log4 xd. xy = 6402 log10 x – log10 y = 2e. log10 a = 2 log10 blog10
Solve, giving your answers correct to 3 sf.a. 22x + 2x+1 – 15 = 0b. 62x – 6x+1 + 7 = 0c. 32x – 2(3x+1) + 8 = 0d. 42x+1 = 17 (4x) - 15
a. Express log4 x in terms of log2 x.b. Using your answer of part a, and the substitution u = log2 x, solve the equation log4 x + log2 x = 12.
Solve, giving your answers correct to 3 sf.a. ln x = 3b. ln x = - 2c. ln (c + 1) = 7d. ln (2x – 5) = 3
Express lg a + 3lg b – 3 as a single logarithm.
Given that log4 p = x and log4 q = y, express in terms of x and/ or ya. log4 (4p)b. log4 (16/p)c. log4p + log4 q2d. pq.
a. Show that lg(x2 y) = 18 can be written as 2 lg x + lg y = 18.b. lg(x2 y) = 18 and lg (x/y3) = 2.Find the value of lg x and lg y.
Solve.a. log2 x + 5 log4 x = 14b. log3 x + 2 log9 x = 4c. 5 log2 x – log4 x = 3d. 4 log3 x = log9 x + 2
Solve, giving your answers correct to 3 sf.a. 4x – 3(2x) – 10 = 0b. 16x + 2(4x) – 25 = 0c. 9x – 2(3x+1) + 8 = 0d. 25x + 20 = 12(5x)
Solve, giving your answers correct to 3 sf.a. ln x3 + ln x = 5b. e3x+4 = 2ex- 1c. ln(x + 5) – ln x = 3
Using the substitution u = 5x, or otherwise, solve52x+1 = 7 (5x) – 2.
Given that loga x = 5 and loga y = 8, finda. loga (1/y)b. loga (√x/y)c. loga (xy)d. loga (x2y3).
a. Express logx 3 in terms of a logarithm to base 3.b. Using your answer of part a, and the substitution u = log3 x, solve the equation log3 x = 3 – 2logx 3.
32x+1 × 5x-1 = 27x × 52xFind the value ofa. 15xb. x.
Solve, giving your answers in exact form.a. ln(x – 3) = 2b. e2x-1 = 7c. e2x – 4ex = 0d. ex = 2e-xe. e2x – 9ex + 20 = 0f. ex + 6e-x = 5
The temperature, T° Celsius, of an object, t minutes after it is removed from a heat source, is given byT = 55 e-0.1t + 15.a. Find the temperature of the object at the instant it is removed from the
Given that loga x = 12 and loga y = 4, find the value ofa. loga (x/y)b. loga (x2/y)c. loga (x√y)d. loga (y/3√x).
Solve.a. log3 x = 9 logx 3b. log5 x + logx 5 = 2c. log4 x – 4 logx 4 + 4 = 0d. log4 x + 6 logx 4 – 5 = 0e. log2 x – 9 logx 2 = 8f. log5 y = 4 – 4 logy 5
Solve the equations, giving your answers correct to 3 significant figures.a. |3x + 2| = |3x – 10|b. |2x+1 + 3| = |2x + 10|c. 32|x| = 5(3|x|) + 24d. 4|x| = 5(2|x|) + 14
Solve, giving your answers correct to 3 sf.a. e2x – 2ex – 24 = 0b. e2x – 5ex + 4 = 0c. ex + 2e-x = 80
a. Write log27 x as a logarithm to base 3.b. Given that loga y = 3(loga 15 – loga 3) + 1, express y in terms of a.
a. Express log4 x in terms of log2 x.b. Express log8 y in terms of log2 y.c. Hence solve, the simultaneous equations6 log4 x + 3 log8 y = 16log2 x – 2 log4 y = 4
Solve the inequality |2x+1 – 1| < 2x – 8| giving your answer in exact form.
Solve the simultaneous equations, giving your answers in exact form.a. ln x = 2 ln yln y – ln x = 1b. e5x-y = 3e3xe2x = 5ex+y
Do not use a calculator in this question.i. Find the value of – logP P2.ii. Find lg(1/10n).iii. Show that lg20-lg4/log5 10 = (lg y)2, where y is a constant to be found.iv. Solve logt 2x + logt 3x =
Solve the simultaneous equations2 log3 y = log5 125 + log3 x2y = 4x.
Solve 5 ln(7 – e2x) = 3, giving your answer correct to 3 significant figures.
a. i. Sketch the graph of y = ex – 5, showing the exact coordinates of any points where the graph meets the coordinate axes.ii. Find the range of values of k for which the equation ex – 5 = k has
Solve ex – xe5x-1 = 0.
a. Solve the following equations to find P and q.8q-1 × 22P+1 = 479P-4 × 3q = 81b. Solve the equation lg(3x – 2) + lg(x + 1) = 2 – lg 2.
Solve 5x2 – x2 e2x + 2e2x = 10 giving your answers in exact form.
Find the real values of x satisfying the following equations.a. x4 – 5x2 + 4 = 0b. x4 + x2 – 6 = 0c. x4 – 20x2 + 64 = 0d. x4 + 2x2 – 8 = 0e. x4 – 4x2 – 21 = 0f. 2x4 – 17x2 – 9 = 0g.
Solve the equation |2x – 3| = |3x – 5|.
Solve.a. |2x – 1| = |x|b. |x + 5| = |x – 4|c. |2x – 3| = |4 – x|d. |5x + 1| = |1 – 3x|e. |1 -4x| = |2 - x|f.g.|3x - 2| = |2x + 5|h. |2x - 1| = 2|3 - x|i. =|3x+2| 2|
The graphs of y = |x – 2| and y = |2x – 10| are shown on the grid.Write down the set of values of x that satisfy the inequality |x – 2|> |2x – 10|. 8- 7- y = Ix -2| 6- 5- 4- y 12x-10| !!
Find the coordinates of the points A, B and C where the curve intercepts the x-axis and the point D where the curve intercepts the positive y-axis. y = (x- 2) (x + 1)(x-3) D A B
The diagram shows part of the graph of y = x(x – 2) (x + 1).Use the graph to solve each of the following inequalities.a. x(x – 2) (x + 1) ≤ 0,b. x(x – 2) (x + 1) ≥ 1,c. x(x – 2) (x + 1)
Use the quadratic formula to solve these equations.Write your answers correct to 3 significant figures.a. x4 – 8x2 + 1 = 0b. x4 – 5x2 – 2 = 0c. 2x4 + x2 – 5 = 0d. 2x6 – 3x3 – 8 = 0e. 3x6
Solve the inequality |2x – 1| > 7.
Solve the simultaneous equations y = |x – 5| and y = |8 – x|.
a. On the same axes sketch the graphs of y = |3x – 6| and y = |4 – x|.b. Solve the inequality |3x – 6| ≥ |4 – x|.
Sketch each of these curves and indicate clearly the axis intercepts.a. y = (x – 2) (x – 4) (x + 3)b. y = (x + 2) (x + 1) (3 – x)c. y = (2x + 1) (x + 2) (x -2)d. y = (3 – 2x) (x – 1) (x + 1)
The diagram shows part of the graph of y = (x + 1)2 (2 - x).Use the graph to solve each of the following inequalities.a. (x + 1)2 (2 - x) ≥ 0,b. (x + 1)2 (2 - x) ≤ 4,c. (x + 1)2 (2 - x) ≤ 3. yt
Solve.a.b.c.d.e. 8x - 18√x + 9 = 0f. 6x + 11√x – 35 = 0g. 2x + 4 = 9√xh.i. x-7Vx+10=0
Solve the inequality |7 – 5x| < 3.
Solve the equation 6|x + 2|2 + 7|x + 2| - 3 = 0.
Solve.a. |2x – 3| > 5b. |4 – 5x| ≤ 9c. |8 – 3x| < 2d. |2x – 7| > 3e. |3x + 1| > 8f. |5 – 2x| ≤ 7
Find the coordinates of the point A and the point B, where A is the point where the curve intercepts the positive x-axis and B is the point where the curve intercepts the positive y-axis. y = 2(x+ 1)
The diagram shows part of the graph of y = (1 – x) (x – 2) (x + 1)Use the graph to solve each of the following inequalities.a. (1 – x) (x – 2) (x + 1) ≤ - 3.b. (1 – x) (x – 2) (x + 1)
Solve the equation 2x2/3 – 7x1/3 + 6 = 0.
Solve the inequality |x| > |3x – 2|.
a. Solve the equation x2 – 6|x| + 8 = 0.b. Use graphing software to draw the graph of f(x) = x2 – 6|x| + 8.c. Use your graph in part b to find the range of the function f.
a. Solve |2x – 3| ≤ x – 1b. |5 + x| > 7 – 2xc. |x – 2| - 3x ≤ 1
Sketch each of these curves and indicate clearly the axis intercepts.a. y = x2(x + 2)b. y = x2(5 – 2x)c. y = (x +1)2 (x-2)d. y = (x – 2)2 (10 – 3x)
The curve y = √x and the line 5y = x + 4 intersect at the points P and Q.a. Write down an equation satisfied by the x-coordinates of P and Q.b. Solve your equation in part a and hence find the
Solve the inequality |x – 1| ≤ |x + 2|.
Solve the equation |x + 1| + |2x – 3| = 8.
Solve.a. |2x – 1| ≤ |3x|b. |x + 1| > |x|c. |x| > |3x – 2|d. |4x + 3| > |x|e. |x + 3| ≥ |2x|f. |2x| < |x – 3|
Sketch each of these curves and indicate clearly the axis intercepts.a. y = |(x + 1) (x – 2) (x – 3)|b. y = |2(5 – 2x) (x + 1) (x + 2)|c. y = |x(9 – x2)|d. y = |3(x – 1)2 (x + 1)|
Solve.a. 22x – 6(2x) + 8 = 0b. 32x – 10(3x) + 9 = 0c. 2(22x) – 9 (2x) + 4 = 0d. 32x+1 – 28(3x) + 9 = 0e. 22x+2 – 33(2x) + 8 = 0f. 32x+2 + 3(3x) – 2 = 0
Solve the inequality |x + 2| < |1/2x – 1|.
Solve the simultaneous equation y = |x – 5| and y = |3 – 2x| + 2.
Solve.a. |x + 1| > |x – 4|b. |x – 2| ≥ |x + 5|c. |x + 1| ≤ |3x + 5|d. |2x + 3| ≤ |x – 3|e. |x + 2| < |1/2x – 5|f. |3x – 2| ≥ |x + 4|
Factorise each of these functions and then sketch the graph of each function indicating clearly the axi intercepts.a. y = 9x – x3b. y = x3 + 4x2 + x – 6c. y = 2x3 + x2 – 25x + 12d. y = 2x3 +
Solve the inequality |x + 3k| < 4|x – k| where k is a positive constant.
The diagram shows the graph of y = k(x – a)2 (x – b).Find the values of a, b and k. -i 2.
Sketch the graph of y = 2(2x – 1) (x – 3) (x + 1), showing clearly the points at which the curve meets the coordinate axes.
Solve |3x + 2| + |3X – 2| ≤ 8.
The diagram shows the graph of y = |k(x – a) (x – b) (x – c)| where a < b < c.Find the values of a, b, c and k. 8- 4- -2-
The diagram shows part of the graph of y = 2(x + 1) (x – 1) (2 – x).Use the graph to solve the inequality (x +1) (x – 1) (2 – x) > - 1. 2- y =2 (x+ 1) (x- 1) (2 - x) -1 -3 -1
Showing 1000 - 1100
of 1718
First
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18