Suppose you are doing a batch steam distillation of a mixture that has two volatile organic compounds,

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Suppose you are doing a batch steam distillation of a mixture that has two volatile organic compounds, n-octane and \(n\)-decane, that are immiscible in water plus a nonvolatile organic compound that is also immiscible in water. The total pressure is \(0.98 \mathrm{bar}\), and the mole fractions of n-octane and n-decane are 0.22 and 0.14 , respectively, in the organic liquid. If the \(\mathrm{n}\)-octane and \(\mathrm{n}\)-decane follow Raoult's law in the organic liquid, what is the temperature of the still pot, and what are the mole fractions of n-octane, n-decane, and water in the vapor?

Data: Green and Perry (2008, Table 2-8) VP in Pa, T in K:

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\(\ln (\mathrm{VP})=\mathrm{C} 1+\mathrm{C} 2 / \mathrm{T}+\mathrm{C} 3 \ln \mathrm{T}+\mathrm{C} 4 \mathrm{~T}^{\mathrm{C} 5}\)

decane: \(\mathrm{C} 1=112.73, \mathrm{C} 2=-9749.6, \mathrm{C} 3=-13.245, \mathrm{C} 4=7.1266 \mathrm{E}-06, \mathrm{C} 5\)

\(=2\)

octane: \(\mathrm{C} 1=96.084, \mathrm{C} 2=-7900.2, \mathrm{C} 3=-11.003, \mathrm{C} 4=7.1802 \mathrm{E}-06, \mathrm{C} 5\)

\(=2\)

water: \(\mathrm{C} 1=73.649, \mathrm{C} 2=-7258.2, \mathrm{C} 3=-7.3037, \mathrm{C} 4=4.1653 \mathrm{E}-06, \mathrm{C} 5\) \(=2\)

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