A proton moves through a uniform magnetic field given by B = (10i - 20j + 30k)
Question:
A proton moves through a uniform magnetic field given by B = (10i - 20j + 30k) m T. At time t1, the proton has a velocity given by v = vx i + vy j + (2.0 km/s) k and the magnetic force on the proton is FB = (4.0 x 10-17 N) i + (2.0 x 10-17 N) j. At that instant, what are?
(a) v x and
(b) v y?
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The magnetic force on the proton is F qvx B w...View the full answer
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Related Book For 
Fundamentals of Physics
ISBN: 978-0471758013
8th Extended edition
Authors: Jearl Walker, Halliday Resnick
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