A solution was prepared by mixing 25.00 mL of 0.080 0 M aniline, 25.00 mL of 0.060
Question:
A solution was prepared by mixing 25.00 mL of 0.080 0 M aniline, 25.00 mL of 0.060 0 M sulfanilic acid, and 1.00 mL of 1.23 × 10-4 M HIn and then diluting to 100.0 mL. (HIn stands for protonated indicator.)
The absorbance measured at 550 nm in a 5.00-cm cell was 0.110. Find the concentrations of HIn and In- and pKa for HIn.
Fantastic news! We've Found the answer you've been seeking!
Step by Step Answer:
Related Book For
Question Posted: