A solution was prepared by mixing 25.00 mL of 0.080 0 M aniline, 25.00 mL of 0.060

Question:

A solution was prepared by mixing 25.00 mL of 0.080 0 M aniline, 25.00 mL of 0.060 0 M sulfanilic acid, and 1.00 mL of 1.23 × 10-4 M HIn and then diluting to 100.0 mL. (HIn stands for protonated indicator.)

NH3

The absorbance measured at 550 nm in a 5.00-cm cell was 0.110. Find the concentrations of HIn and In- and pKa for HIn.

Fantastic news! We've Found the answer you've been seeking!

Step by Step Answer:

Related Book For  book-img-for-question
Question Posted: