Aluminum hydroxide reacts with sulfuric acid as follows: Which is the limiting reactant when 0.500 mol Al(OH)3

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Aluminum hydroxide reacts with sulfuric acid as follows:

Which is the limiting reactant when 0.500 mol Al(OH)3 and 0.500 mol H2SO4 are allowed to react? How many moles of Al2(SO4)3 can form under these conditions? How many moles of the excess reactant remain after the completion of the reaction?

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Chemistry The Central Science

ISBN: 978-0321696724

12th edition

Authors: Theodore Brown, Eugene LeMay, Bruce Bursten, Catherine Murphy, Patrick Woodward

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Question Posted: Apr 19, 2016 06:50 AM

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Aluminum hydroxide reacts with sulfuric acid as follows: Which is the limiting reactant when 0.500 mol Al(OH)3

Question:

2 AI(OH)3(s) 3 H SO4(aą) Al2(SO4)3(a) 6 H2O()

Step by Step Answer:

0500 mol AlOH 3 3 mol H 2 SO 4 2 mol Al OH 3 0750 mol H 2 SO 4 neeed for com...View the full answer

Chemistry The Central Science

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