Apply Eqs. 7.7 and 7.10 directly to Eqs. 7.1 and 7.2 and derive the relations of Eqs.
Question:
Eq. 7.1
du = Tds - Pdv
Eq. 7.2
dh = Tds + vdP
Eq. 7.7
dz = (∂z/∂x)y dx + (∂z/∂y)x dy
Eq. 7.11
(∂T/∂v)s = - (∂P/∂s)v
Eq. 7.12
(∂T/∂P)s = (∂v/∂s)P
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Related Book For
Thermodynamics for Engineers
ISBN: ?978-1133112860
1st edition
Authors: Kenneth A. Kroos, Merle C. Potter
Question Posted:
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