Calculate the rate of heat transfer between a 15-cm-OD pipe at 120?C and a 10-cm-OD pipe at 40?C. The two pipes are 330 m long and are buried in sand [k = 0.33W/(m K)] 12 m below the surface (Ts = 25?C). The pipes are parallel and are separated by 23 cm (center to center) distance.GIVENTwo parallel pipes buried in sandPipe 1Outside diameter (D1) = 15 cm = 0.15 mTemperature (T1) = 120?CPipe 2Outside diameter (D2) = 10 cm = 0.1 mTemperature (T2) = 40?CLength of pipes (L) = 330 mThermal conductivity of the sand (k) = 0.33 W/(m K)Depth below surface (d) = 1.2 mSurface temperature (Ts) = 25?CCenter to center distance between pipes (s) = 23 cm = 0.23 mASSUMPTIONSThe thermal conductivity of the sand is uniformTwo dimensional, steady state heattransfer

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T 25° C d= 1.2 m $-23 cm HO,- 40°c T = 120°C D, = 15 cm D2- 10 cm