Consider the following fusion reaction, through which stars produce progressively heavier elements: 32He + 42He → 74Be + γ. The mass of 32He is 3.016029 u, the mass of 42He is 4.002603 u, and the mass of 74Be is 7.0169298 u. The atomic mass unit is 1 u = 1.66∙10-27 kg. Assuming that the Be atom is at rest after the reaction and neglecting any potential energy between the atoms and the kinetic energy of the He nuclei, calculate the minimum possible energy and maximum possible wavelength of the photon, y, that is emitted in this reaction.