Consider the induced nuclear reaction 2 1 H + 14 7 H 12 6 C +
Question:
Consider the induced nuclear reaction 21H + 147H → 126C + 42He. The atomic masses are 21H (2.014 102 u), 147N (14.003 074 u), 126C (12.000 000 u), and 42He (4.002 603 u). Determine the energy (in MeV) released by the reaction.
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Energy is released from this reaction Consequently the combined ...View the full answer
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